13110033001013 has 4 divisors (see below), whose sum is σ = 14118497078028. Its totient is φ = 12101568924000.

The previous prime is 13110033000937. The next prime is 13110033001141. The reversal of 13110033001013 is 31010033001131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7378519293649 + 5731513707364 = 2716343^2 + 2394058^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13110033001013 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13110033000982 and 13110033001000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110033003013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 504232038488 + ... + 504232038513.

It is an arithmetic number, because the mean of its divisors is an integer number (3529624269507).

Almost surely, 2^{13110033001013} is an apocalyptic number.

13110033001013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13110033001013 is a deficient number, since it is larger than the sum of its proper divisors (1008464077015).

13110033001013 is a wasteful number, since it uses less digits than its factorization.

13110033001013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1008464077014.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 13110033001013 its reverse (31010033001131), we get a palindrome (44120066002144).

The spelling of 13110033001013 in words is "thirteen trillion, one hundred ten billion, thirty-three million, one thousand, thirteen".