Base | Representation |
---|---|
bin | 1011111011000110101011… |
… | …1100111010101101011101 |
3 | 1201102022021211220101112212 |
4 | 2332301222330322231131 |
5 | 3204243322320311110 |
6 | 43514400002410205 |
7 | 2522111606643554 |
oct | 276615274725535 |
9 | 51368254811485 |
10 | 13110034541405 |
11 | 41a4a307a231a |
12 | 1578990060965 |
13 | 74136a38a409 |
14 | 334759a3ad9b |
15 | 17b04e803e05 |
hex | bec6af3ab5d |
13110034541405 has 4 divisors (see below), whose sum is σ = 15732041449692. Its totient is φ = 10488027633120.
The previous prime is 13110034541389. The next prime is 13110034541413. The reversal of 13110034541405 is 50414543001131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 7907192152729 + 5202842388676 = 2811973^2 + 2280974^2 .
It is not a de Polignac number, because 13110034541405 - 24 = 13110034541389 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1311003454136 + ... + 1311003454145.
It is an arithmetic number, because the mean of its divisors is an integer number (3933010362423).
Almost surely, 213110034541405 is an apocalyptic number.
It is an amenable number.
13110034541405 is a deficient number, since it is larger than the sum of its proper divisors (2622006908287).
13110034541405 is an equidigital number, since it uses as much as digits as its factorization.
13110034541405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2622006908286.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 13110034541405 its reverse (50414543001131), we get a palindrome (63524577542536).
The spelling of 13110034541405 in words is "thirteen trillion, one hundred ten billion, thirty-four million, five hundred forty-one thousand, four hundred five".
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