13110047 has 2 divisors, whose sum is σ = 13110048. Its totient is φ = 13110046.

The previous prime is 13109983. The next prime is 13110073. The reversal of 13110047 is 74001131.

It is a strong prime.

It is an emirp because it is prime and its reverse (74001131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13110047 - 2⁶ = 13109983 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13110347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555023 + 6555024.

It is an arithmetic number, because the mean of its divisors is an integer number (6555024).

Almost surely, 2^13110047 is an apocalyptic number.

13110047 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110047 is an equidigital number, since it uses as much as digits as its factorization.

13110047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84, while the sum is 17.

The square root of 13110047 is about 3620.7798883666. The cubic root of 13110047 is about 235.7950857020.

Adding to 13110047 its reverse (74001131), we get a palindrome (87111178).

The spelling of 13110047 in words is "thirteen million, one hundred ten thousand, forty-seven".