Base | Representation |
---|---|
bin | 11000011010110101… |
… | …11000101001111100 |
3 | 1020211122212201111001 |
4 | 30031122320221330 |
5 | 203322133203000 |
6 | 10004521540044 |
7 | 642610421215 |
oct | 141532705174 |
9 | 36748781431 |
10 | 13110053500 |
11 | 5618313265 |
12 | 265a644624 |
13 | 130c12550b |
14 | 8c521640c |
15 | 51ae4046a |
hex | 30d6b8a7c |
13110053500 has 48 divisors (see below), whose sum is σ = 29172648960. Its totient is φ = 5145067200.
The previous prime is 13110053479. The next prime is 13110053507. The reversal of 13110053500 is 535001131.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13110053507) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 220860 + ... + 273859.
It is an arithmetic number, because the mean of its divisors is an integer number (607763520).
Almost surely, 213110053500 is an apocalyptic number.
13110053500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13110053500 is an abundant number, since it is smaller than the sum of its proper divisors (16062595460).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13110053500 is a wasteful number, since it uses less digits than its factorization.
13110053500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 494791 (or 494779 counting only the distinct ones).
The product of its (nonzero) digits is 225, while the sum is 19.
Adding to 13110053500 its reverse (535001131), we get a palindrome (13645054631).
The spelling of 13110053500 in words is "thirteen billion, one hundred ten million, fifty-three thousand, five hundred".
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