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131102122013 is a prime number
BaseRepresentation
bin111101000011001001…
…0111010000000011101
3110112101201202211210122
41322012102322000131
54121444120401023
6140121045244325
712320555436032
oct1720622720035
9415351684718
10131102122013
1150666803775
12214a9a036a5
13c494319335
1464b99db389
1536249b82c8
hex1e864ba01d

131102122013 has 2 divisors, whose sum is σ = 131102122014. Its totient is φ = 131102122012.

The previous prime is 131102121929. The next prime is 131102122043. The reversal of 131102122013 is 310221201131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 71662219204 + 59439902809 = 267698^2 + 243803^2 .

It is a cyclic number.

It is not a de Polignac number, because 131102122013 - 218 = 131101859869 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131102121982 and 131102122000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131102122043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65551061006 + 65551061007.

It is an arithmetic number, because the mean of its divisors is an integer number (65551061007).

Almost surely, 2131102122013 is an apocalyptic number.

It is an amenable number.

131102122013 is a deficient number, since it is larger than the sum of its proper divisors (1).

131102122013 is an equidigital number, since it uses as much as digits as its factorization.

131102122013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 131102122013 its reverse (310221201131), we get a palindrome (441323323144).

The spelling of 131102122013 in words is "one hundred thirty-one billion, one hundred two million, one hundred twenty-two thousand, thirteen".