Base | Representation |
---|---|
bin | 111101000011001011… |
… | …0101100000001010111 |
3 | 110112101210122012121002 |
4 | 1322012112230001113 |
5 | 4121444344111203 |
6 | 140121122413515 |
7 | 12320600035061 |
oct | 1720626540127 |
9 | 415353565532 |
10 | 131103113303 |
11 | 50667320518 |
12 | 214aa20129b |
13 | c4945a55b6 |
14 | 64b9bb8731 |
15 | 3624b11d88 |
hex | 1e865ac057 |
131103113303 has 4 divisors (see below), whose sum is σ = 136803248688. Its totient is φ = 125402977920.
The previous prime is 131103113299. The next prime is 131103113347. The reversal of 131103113303 is 303311301131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 303311301131 = 17 ⋅17841841243.
It is a cyclic number.
It is not a de Polignac number, because 131103113303 - 22 = 131103113299 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131103113363) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2850067658 + ... + 2850067703.
It is an arithmetic number, because the mean of its divisors is an integer number (34200812172).
Almost surely, 2131103113303 is an apocalyptic number.
131103113303 is a deficient number, since it is larger than the sum of its proper divisors (5700135385).
131103113303 is an equidigital number, since it uses as much as digits as its factorization.
131103113303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5700135384.
The product of its (nonzero) digits is 243, while the sum is 20.
Adding to 131103113303 its reverse (303311301131), we get a palindrome (434414414434).
The spelling of 131103113303 in words is "one hundred thirty-one billion, one hundred three million, one hundred thirteen thousand, three hundred three".
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