Base | Representation |
---|---|
bin | 111101000011001011… |
… | …1110011000111010101 |
3 | 110112101211012000001012 |
4 | 1322012113303013111 |
5 | 4121444432421001 |
6 | 140121132542005 |
7 | 12320602360046 |
oct | 1720627630725 |
9 | 415354160035 |
10 | 131103404501 |
11 | 506674aa283 |
12 | 214aa321905 |
13 | c494677cc4 |
14 | 64b9c528cd |
15 | 3624b6d2bb |
hex | 1e865f31d5 |
131103404501 has 2 divisors, whose sum is σ = 131103404502. Its totient is φ = 131103404500.
The previous prime is 131103404491. The next prime is 131103404581. The reversal of 131103404501 is 105404301131.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 128880282001 + 2223122500 = 358999^2 + 47150^2 .
It is a cyclic number.
It is not a de Polignac number, because 131103404501 - 222 = 131099210197 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131103404581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65551702250 + 65551702251.
It is an arithmetic number, because the mean of its divisors is an integer number (65551702251).
Almost surely, 2131103404501 is an apocalyptic number.
It is an amenable number.
131103404501 is a deficient number, since it is larger than the sum of its proper divisors (1).
131103404501 is an equidigital number, since it uses as much as digits as its factorization.
131103404501 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 131103404501 its reverse (105404301131), we get a palindrome (236507705632).
The spelling of 131103404501 in words is "one hundred thirty-one billion, one hundred three million, four hundred four thousand, five hundred one".
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