Base | Representation |
---|---|
bin | 1011111011001000000011… |
… | …0100011100111001010111 |
3 | 1201102100020102020210120211 |
4 | 2332302000310130321113 |
5 | 3204300100230432022 |
6 | 43514500230110251 |
7 | 2522123653242211 |
oct | 276620064347127 |
9 | 51370212223524 |
10 | 13110401420887 |
11 | 41a50a98a6301 |
12 | 1578a72aab387 |
13 | 7413c83a3574 |
14 | 33479265d5b1 |
15 | 17b071b23e77 |
hex | bec80d1ce57 |
13110401420887 has 2 divisors, whose sum is σ = 13110401420888. Its totient is φ = 13110401420886.
The previous prime is 13110401420861. The next prime is 13110401420891. The reversal of 13110401420887 is 78802410401131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13110401420887 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13110401420387) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555200710443 + 6555200710444.
It is an arithmetic number, because the mean of its divisors is an integer number (6555200710444).
Almost surely, 213110401420887 is an apocalyptic number.
13110401420887 is a deficient number, since it is larger than the sum of its proper divisors (1).
13110401420887 is an equidigital number, since it uses as much as digits as its factorization.
13110401420887 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43008, while the sum is 40.
The spelling of 13110401420887 in words is "thirteen trillion, one hundred ten billion, four hundred one million, four hundred twenty thousand, eight hundred eighty-seven".
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