Base | Representation |
---|---|
bin | 1011111011001000000011… |
… | …0110110101000110111001 |
3 | 1201102100020110102110210212 |
4 | 2332302000312311012321 |
5 | 3204300100410404340 |
6 | 43514500251320505 |
7 | 2522123661446654 |
oct | 276620066650671 |
9 | 51370213373725 |
10 | 13110402044345 |
11 | 41a50aa191761 |
12 | 1578a73150135 |
13 | 7413c8561288 |
14 | 33479278289b |
15 | 17b071be8a65 |
hex | bec80db51b9 |
13110402044345 has 8 divisors (see below), whose sum is σ = 15758747035200. Its totient is φ = 10470811914160.
The previous prime is 13110402044339. The next prime is 13110402044359. The reversal of 13110402044345 is 54344020401131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13110402044345 - 24 = 13110402044329 is a prime.
It is a Curzon number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2188711871 + ... + 2188717860.
It is an arithmetic number, because the mean of its divisors is an integer number (1969843379400).
Almost surely, 213110402044345 is an apocalyptic number.
It is an amenable number.
13110402044345 is a deficient number, since it is larger than the sum of its proper divisors (2648344990855).
13110402044345 is an equidigital number, since it uses as much as digits as its factorization.
13110402044345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4377430335.
The product of its (nonzero) digits is 23040, while the sum is 32.
Adding to 13110402044345 its reverse (54344020401131), we get a palindrome (67454422445476).
The spelling of 13110402044345 in words is "thirteen trillion, one hundred ten billion, four hundred two million, forty-four thousand, three hundred forty-five".
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