Base | Representation |
---|---|
bin | 10011000101000011101… |
… | …101011100010010111101 |
3 | 11122100011212212020200122 |
4 | 103011003231130102331 |
5 | 132440113324324013 |
6 | 2442151140504325 |
7 | 163503206500334 |
oct | 23050355342275 |
9 | 4570155766618 |
10 | 1311101011133 |
11 | 466042382161 |
12 | 1921250ab0a5 |
13 | 96836c2a894 |
14 | 47659a30d1b |
15 | 241887b8a08 |
hex | 13143b5c4bd |
1311101011133 has 2 divisors, whose sum is σ = 1311101011134. Its totient is φ = 1311101011132.
The previous prime is 1311101011117. The next prime is 1311101011141. The reversal of 1311101011133 is 3311101011131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1159233362329 + 151867648804 = 1076677^2 + 389702^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311101011133 - 24 = 1311101011117 is a prime.
It is a super-2 number, since 2×13111010111332 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311101011333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655550505566 + 655550505567.
It is an arithmetic number, because the mean of its divisors is an integer number (655550505567).
Almost surely, 21311101011133 is an apocalyptic number.
It is an amenable number.
1311101011133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311101011133 is an equidigital number, since it uses as much as digits as its factorization.
1311101011133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27, while the sum is 17.
Adding to 1311101011133 its reverse (3311101011131), we get a palindrome (4622202022264).
The spelling of 1311101011133 in words is "one trillion, three hundred eleven billion, one hundred one million, eleven thousand, one hundred thirty-three".
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