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13111031220000 = 25354731216741
BaseRepresentation
bin1011111011001010011001…
…0110111100011100100000
31201102101212022022220112220
42332302212112330130200
53204302342443020000
643515042524551040
72522145401402220
oct276624626743440
951371768286486
1013111031220000
1141a53a235773a
1215790099b2480
13741498a0386c
14334812162080
1517b0ac07b1a0
hexbeca65bc720

13111031220000 has 240 divisors, whose sum is σ = 49150635412032. Its totient is φ = 2996807040000.

The previous prime is 13111031219999. The next prime is 13111031220011. The reversal of 13111031220000 is 2213011131.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (240).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 15188371 + ... + 16028370.

Almost surely, 213111031220000 is an apocalyptic number.

13111031220000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13111031220000 is an abundant number, since it is smaller than the sum of its proper divisors (36039604192032).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13111031220000 is an equidigital number, since it uses as much as digits as its factorization.

13111031220000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31216781 (or 31216758 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 13111031220000 its reverse (2213011131), we get a palindrome (13113244231131).

The spelling of 13111031220000 in words is "thirteen trillion, one hundred eleven billion, thirty-one million, two hundred twenty thousand".