13111220213 has 16 divisors (see below), whose sum is σ = 16147022976. Its totient is φ = 10367196480.

The previous prime is 13111220191. The next prime is 13111220231. The reversal of 13111220213 is 31202211131.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13111220213 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13111220191 and 13111220200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111220263) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 103070 + ... + 191952.

It is an arithmetic number, because the mean of its divisors is an integer number (1009188936).

Almost surely, 2^13111220213 is an apocalyptic number.

13111220213 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13111220213 is a deficient number, since it is larger than the sum of its proper divisors (3035802763).

13111220213 is a wasteful number, since it uses less digits than its factorization.

13111220213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 90524.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13111220213 its reverse (31202211131), we get a palindrome (44313431344).

The spelling of 13111220213 in words is "thirteen billion, one hundred eleven million, two hundred twenty thousand, two hundred thirteen".