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13111221023 is a prime number
BaseRepresentation
bin11000011010111110…
…10101101100011111
31020211202002001000122
430031133111230133
5203322433033043
610005002545155
7642623353115
oct141537255437
936752061018
1013111221023
115618a4045a
12265ab081bb
13130c443a64
148c543bab5
1551b0c1368
hex30d7d5b1f

13111221023 has 2 divisors, whose sum is σ = 13111221024. Its totient is φ = 13111221022.

The previous prime is 13111220987. The next prime is 13111221029. The reversal of 13111221023 is 32012211131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13111221023 - 216 = 13111155487 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13111220992 and 13111221010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13111221029) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555610511 + 6555610512.

It is an arithmetic number, because the mean of its divisors is an integer number (6555610512).

Almost surely, 213111221023 is an apocalyptic number.

13111221023 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111221023 is an equidigital number, since it uses as much as digits as its factorization.

13111221023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13111221023 its reverse (32012211131), we get a palindrome (45123432154).

The spelling of 13111221023 in words is "thirteen billion, one hundred eleven million, two hundred twenty-one thousand, twenty-three".