13111223120111 has 2 divisors, whose sum is σ = 13111223120112. Its totient is φ = 13111223120110.

The previous prime is 13111223120027. The next prime is 13111223120113. The reversal of 13111223120111 is 11102132211131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13111223120111 - 2¹⁰ = 13111223119087 is a prime.

Together with 13111223120113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13111223120113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555611560055 + 6555611560056.

It is an arithmetic number, because the mean of its divisors is an integer number (6555611560056).

Almost surely, 2^{13111223120111} is an apocalyptic number.

13111223120111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111223120111 is an equidigital number, since it uses as much as digits as its factorization.

13111223120111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 20.

Adding to 13111223120111 its reverse (11102132211131), we get a palindrome (24213355331242).

The spelling of 13111223120111 in words is "thirteen trillion, one hundred eleven billion, two hundred twenty-three million, one hundred twenty thousand, one hundred eleven".