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1311124115503 is a prime number
BaseRepresentation
bin10011000101000101000…
…101100101000000101111
311122100020111100001221001
4103011011011211000233
5132440140233144003
62442153324021131
7163503610046116
oct23050505450057
94570214301831
101311124115503
11466054422884
121921309917a7
139683b959cc7
144765cb26c7d
152418a82e61d
hex1314516502f

1311124115503 has 2 divisors, whose sum is σ = 1311124115504. Its totient is φ = 1311124115502.

The previous prime is 1311124115471. The next prime is 1311124115573. The reversal of 1311124115503 is 3055114211131.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1311124115503 - 25 = 1311124115471 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311124115573) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655562057751 + 655562057752.

It is an arithmetic number, because the mean of its divisors is an integer number (655562057752).

Almost surely, 21311124115503 is an apocalyptic number.

1311124115503 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311124115503 is an equidigital number, since it uses as much as digits as its factorization.

1311124115503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1800, while the sum is 28.

Adding to 1311124115503 its reverse (3055114211131), we get a palindrome (4366238326634).

The spelling of 1311124115503 in words is "one trillion, three hundred eleven billion, one hundred twenty-four million, one hundred fifteen thousand, five hundred three".