Base | Representation |
---|---|
bin | 10011000101000101000… |
… | …101100101000000101111 |
3 | 11122100020111100001221001 |
4 | 103011011011211000233 |
5 | 132440140233144003 |
6 | 2442153324021131 |
7 | 163503610046116 |
oct | 23050505450057 |
9 | 4570214301831 |
10 | 1311124115503 |
11 | 466054422884 |
12 | 1921309917a7 |
13 | 9683b959cc7 |
14 | 4765cb26c7d |
15 | 2418a82e61d |
hex | 1314516502f |
1311124115503 has 2 divisors, whose sum is σ = 1311124115504. Its totient is φ = 1311124115502.
The previous prime is 1311124115471. The next prime is 1311124115573. The reversal of 1311124115503 is 3055114211131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311124115503 - 25 = 1311124115471 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311124115573) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655562057751 + 655562057752.
It is an arithmetic number, because the mean of its divisors is an integer number (655562057752).
Almost surely, 21311124115503 is an apocalyptic number.
1311124115503 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311124115503 is an equidigital number, since it uses as much as digits as its factorization.
1311124115503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1800, while the sum is 28.
Adding to 1311124115503 its reverse (3055114211131), we get a palindrome (4366238326634).
The spelling of 1311124115503 in words is "one trillion, three hundred eleven billion, one hundred twenty-four million, one hundred fifteen thousand, five hundred three".
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