1311127403 has 2 divisors, whose sum is σ = 1311127404. Its totient is φ = 1311127402.

The previous prime is 1311127373. The next prime is 1311127427. The reversal of 1311127403 is 3047211131.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (3047211131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311127403 - 2⁶ = 1311127339 is a prime.

It is not a weakly prime, because it can be changed into another prime (1311127453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655563701 + 655563702.

It is an arithmetic number, because the mean of its divisors is an integer number (655563702).

Almost surely, 2^1311127403 is an apocalyptic number.

1311127403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311127403 is an equidigital number, since it uses as much as digits as its factorization.

1311127403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

The square root of 1311127403 is about 36209.4932717927. The cubic root of 1311127403 is about 1094.4979810626.

Adding to 1311127403 its reverse (3047211131), we get a palindrome (4358338534).

The spelling of 1311127403 in words is "one billion, three hundred eleven million, one hundred twenty-seven thousand, four hundred three".