131113101230 has 8 divisors (see below), whose sum is σ = 236003582232. Its totient is φ = 52445240488.

The previous prime is 131113101221. The next prime is 131113101233. The reversal of 131113101230 is 32101311131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 131113101199 and 131113101208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131113101233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6555655052 + ... + 6555655071.

It is an arithmetic number, because the mean of its divisors is an integer number (29500447779).

Almost surely, 2^131113101230 is an apocalyptic number.

131113101230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131113101230 is a deficient number, since it is larger than the sum of its proper divisors (104890481002).

131113101230 is a wasteful number, since it uses less digits than its factorization.

131113101230 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13111310130.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 131113101230 its reverse (32101311131), we get a palindrome (163214412361).

The spelling of 131113101230 in words is "one hundred thirty-one billion, one hundred thirteen million, one hundred one thousand, two hundred thirty".