Base | Representation |
---|---|
bin | 11101110011111100101011… |
… | …110101111011001000011000 |
3 | 122012020022002111100100202010 |
4 | 131303330223311323020120 |
5 | 114141124314230413422 |
6 | 1142504323520305520 |
7 | 36421421243246325 |
oct | 3563745365731030 |
9 | 565208074310663 |
10 | 131113202201112 |
11 | 3885a88458a32a |
12 | 1285674a1722a0 |
13 | 5820bca5aa281 |
14 | 2453cacbc7b4c |
15 | 102584e0dcb0c |
hex | 773f2bd7b218 |
131113202201112 has 64 divisors (see below), whose sum is σ = 342036156960000. Its totient is φ = 41803999611264.
The previous prime is 131113202201083. The next prime is 131113202201183. The reversal of 131113202201112 is 211102202311131.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 139158339 + ... + 140097357.
It is an arithmetic number, because the mean of its divisors is an integer number (5344314952500).
Almost surely, 2131113202201112 is an apocalyptic number.
131113202201112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
131113202201112 is an abundant number, since it is smaller than the sum of its proper divisors (210922954758888).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131113202201112 is a wasteful number, since it uses less digits than its factorization.
131113202201112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1192000 (or 1191996 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 21.
Adding to 131113202201112 its reverse (211102202311131), we get a palindrome (342215404512243).
The spelling of 131113202201112 in words is "one hundred thirty-one trillion, one hundred thirteen billion, two hundred two million, two hundred one thousand, one hundred twelve".
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