Base | Representation |
---|---|
bin | 1011111011001011011110… |
… | …1000110111110001000111 |
3 | 1201102102121111211222012012 |
4 | 2332302313220313301013 |
5 | 3204303441202211403 |
6 | 43515131402444435 |
7 | 2522155521535055 |
oct | 276626750676107 |
9 | 51372544758165 |
10 | 13111321132103 |
11 | 41a5530a70a17 |
12 | 157908ab0371b |
13 | 741513aaba9c |
14 | 33483c86b1d5 |
15 | 17b0c7745ed8 |
hex | becb7a37c47 |
13111321132103 has 4 divisors (see below), whose sum is σ = 13111384393128. Its totient is φ = 13111257871080.
The previous prime is 13111321132099. The next prime is 13111321132139. The reversal of 13111321132103 is 30123112311131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13111321132103 - 22 = 13111321132099 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13111321132183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31318601 + ... + 31734482.
It is an arithmetic number, because the mean of its divisors is an integer number (3277846098282).
Almost surely, 213111321132103 is an apocalyptic number.
13111321132103 is a deficient number, since it is larger than the sum of its proper divisors (63261025).
13111321132103 is an equidigital number, since it uses as much as digits as its factorization.
13111321132103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63261024.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 13111321132103 its reverse (30123112311131), we get a palindrome (43234433443234).
The spelling of 13111321132103 in words is "thirteen trillion, one hundred eleven billion, three hundred twenty-one million, one hundred thirty-two thousand, one hundred three".
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