131113232042140 has 192 divisors, whose sum is σ = 291783824640000. Its totient is φ = 49390005519360.

The previous prime is 131113232042137. The next prime is 131113232042183. The reversal of 131113232042140 is 41240232311131.

It is a junction number, because it is equal to n+sod(n) for n = 131113232042099 and 131113232042108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 13902363225 + ... + 13902372655.

It is an arithmetic number, because the mean of its divisors is an integer number (1519707420000).

Almost surely, 2^{131113232042140} is an apocalyptic number.

131113232042140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131113232042140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (145891912320000).

131113232042140 is an abundant number, since it is smaller than the sum of its proper divisors (160670592597860).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131113232042140 is a wasteful number, since it uses less digits than its factorization.

131113232042140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11300 (or 11298 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 131113232042140 its reverse (41240232311131), we get a palindrome (172353464353271).

The spelling of 131113232042140 in words is "one hundred thirty-one trillion, one hundred thirteen billion, two hundred thirty-two million, forty-two thousand, one hundred forty".