Base | Representation |
---|---|
bin | 11000011010111111… |
… | …01110111011110101 |
3 | 1020211202021021211121 |
4 | 30031133232323311 |
5 | 203322444340110 |
6 | 10005005103541 |
7 | 642624263404 |
oct | 141537567365 |
9 | 36752237747 |
10 | 13111324405 |
11 | 56190010a3 |
12 | 265ab57bb1 |
13 | 130c47bb2a |
14 | 8c546763b |
15 | 51b0e1cda |
hex | 30d7eeef5 |
13111324405 has 8 divisors (see below), whose sum is σ = 15777417600. Its totient is φ = 10459840656.
The previous prime is 13111324381. The next prime is 13111324417. The reversal of 13111324405 is 50442311131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13111324405 - 231 = 10963840757 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13111324405.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3650385 + ... + 3653974.
It is an arithmetic number, because the mean of its divisors is an integer number (1972177200).
Almost surely, 213111324405 is an apocalyptic number.
It is an amenable number.
13111324405 is a deficient number, since it is larger than the sum of its proper divisors (2666093195).
13111324405 is an equidigital number, since it uses as much as digits as its factorization.
13111324405 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7304723.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 13111324405 its reverse (50442311131), we get a palindrome (63553635536).
The spelling of 13111324405 in words is "thirteen billion, one hundred eleven million, three hundred twenty-four thousand, four hundred five".
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