13111431203035 has 8 divisors (see below), whose sum is σ = 17164055393136. Its totient is φ = 9535586329440.

The previous prime is 13111431203033. The next prime is 13111431203071. The reversal of 13111431203035 is 53030213411131.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13111431203035 - 2¹ = 13111431203033 is a prime.

It is a super-3 number, since 3×13111431203035³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13111431202994 and 13111431203012.

It is not an unprimeable number, because it can be changed into a prime (13111431203033) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 119194829064 + ... + 119194829173.

It is an arithmetic number, because the mean of its divisors is an integer number (2145506924142).

Almost surely, 2^{13111431203035} is an apocalyptic number.

13111431203035 is a deficient number, since it is larger than the sum of its proper divisors (4052624190101).

13111431203035 is a wasteful number, since it uses less digits than its factorization.

13111431203035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 238389658253.

The product of its (nonzero) digits is 3240, while the sum is 28.

Adding to 13111431203035 its reverse (53030213411131), we get a palindrome (66141644614166).

The spelling of 13111431203035 in words is "thirteen trillion, one hundred eleven billion, four hundred thirty-one million, two hundred three thousand, thirty-five".