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13112011301100 = 2235243706704337
BaseRepresentation
bin1011111011001110000011…
…0001101010000011101100
31201102111101121112012001220
42332303200301222003230
53204311344343113400
643515324055303340
72522211602062425
oct276634061520354
951374347465056
1013112011301100
1141a5855606118
12157924207ab50
137415c3a884ca
143348a63a664c
1517b1181257a0
hexbece0c6a0ec

13112011301100 has 36 divisors (see below), whose sum is σ = 37937419365384. Its totient is φ = 3496536346880.

The previous prime is 13112011301009. The next prime is 13112011301101. The reversal of 13112011301100 is 110311021131.

13112011301100 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×131120113011002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 13112011301100.

It is not an unprimeable number, because it can be changed into a prime (13112011301101) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 21853351869 + ... + 21853352468.

It is an arithmetic number, because the mean of its divisors is an integer number (1053817204594).

Almost surely, 213112011301100 is an apocalyptic number.

13112011301100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13112011301100 is an abundant number, since it is smaller than the sum of its proper divisors (24825408064284).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13112011301100 is a wasteful number, since it uses less digits than its factorization.

13112011301100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43706704354 (or 43706704347 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 13112011301100 its reverse (110311021131), we get a palindrome (13222322322231).

The spelling of 13112011301100 in words is "thirteen trillion, one hundred twelve billion, eleven million, three hundred one thousand, one hundred".

Divisors: 1 2 3 4 5 6 10 12 15 20 25 30 50 60 75 100 150 300 43706704337 87413408674 131120113011 174826817348 218533521685 262240226022 437067043370 524480452044 655600565055 874134086740 1092667608425 1311201130110 2185335216850 2622402260220 3278002825275 4370670433700 6556005650550 13112011301100