1311210040103 has 8 divisors (see below), whose sum is σ = 1388366904960. Its totient is φ = 1234056160000.

The previous prime is 1311210040093. The next prime is 1311210040109. The reversal of 1311210040103 is 3010400121131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1311210040103 - 2⁶ = 1311210040039 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (17).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311210040109) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 191978 + ... + 1630728.

It is an arithmetic number, because the mean of its divisors is an integer number (173545863120).

Almost surely, 2^{1311210040103} is an apocalyptic number.

1311210040103 is a deficient number, since it is larger than the sum of its proper divisors (77156864857).

1311210040103 is a wasteful number, since it uses less digits than its factorization.

1311210040103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1492377.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1311210040103 its reverse (3010400121131), we get a palindrome (4321610161234).

The spelling of 1311210040103 in words is "one trillion, three hundred eleven billion, two hundred ten million, forty thousand, one hundred three".