Base | Representation |
---|---|
bin | 100111000100111… |
… | …0111101110111111 |
3 | 10101101021101120022 |
4 | 1032021313232333 |
5 | 10141132213211 |
6 | 334035442355 |
7 | 44331050636 |
oct | 11611675677 |
9 | 3341241508 |
10 | 1311210431 |
11 | 613164893 |
12 | 3071563bb |
13 | 17b86177b |
14 | c61dc51d |
15 | 7a1a6bdb |
hex | 4e277bbf |
1311210431 has 2 divisors, whose sum is σ = 1311210432. Its totient is φ = 1311210430.
The previous prime is 1311210413. The next prime is 1311210457. The reversal of 1311210431 is 1340121131.
Together with previous prime (1311210413) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311210431 - 26 = 1311210367 is a prime.
It is a super-2 number, since 2×13112104312 = 3438545588726411522, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311210931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655605215 + 655605216.
It is an arithmetic number, because the mean of its divisors is an integer number (655605216).
Almost surely, 21311210431 is an apocalyptic number.
1311210431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311210431 is an equidigital number, since it uses as much as digits as its factorization.
1311210431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
The square root of 1311210431 is about 36210.6397485601. The cubic root of 1311210431 is about 1094.5210838417.
Adding to 1311210431 its reverse (1340121131), we get a palindrome (2651331562).
The spelling of 1311210431 in words is "one billion, three hundred eleven million, two hundred ten thousand, four hundred thirty-one".
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