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1311212123100 = 22325211293452033
BaseRepresentation
bin10011000101001010010…
…101010011001111011100
311122100110121221022122200
4103011022111103033130
5132440330300414400
62442210150211500
7163506026103045
oct23051225231734
94570417838580
101311212123100
1146609a073230
12192156353b90
1396853c620c9
144766a6b58cc
1524193415b00
hex1314a5533dc

1311212123100 has 216 divisors, whose sum is σ = 4498862960592. Its totient is φ = 316784025600.

The previous prime is 1311212123099. The next prime is 1311212123101. The reversal of 1311212123100 is 13212121131.

1311212123100 is a `hidden beast` number, since 1 + 311 + 2 + 121 + 231 + 0 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (1311212123099) and next prime (1311212123101).

It is a super-2 number, since 2×13112121231002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311212123101) by changing a digit.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 2674684 + ... + 3126716.

It is an arithmetic number, because the mean of its divisors is an integer number (20828069262).

Almost surely, 21311212123100 is an apocalyptic number.

1311212123100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1311212123100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2249431480296).

1311212123100 is an abundant number, since it is smaller than the sum of its proper divisors (3187650837492).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311212123100 is a wasteful number, since it uses less digits than its factorization.

1311212123100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 452357 (or 452347 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 1311212123100 its reverse (13212121131), we get a palindrome (1324424244231).

The spelling of 1311212123100 in words is "one trillion, three hundred eleven billion, two hundred twelve million, one hundred twenty-three thousand, one hundred".