Base | Representation |
---|---|
bin | 111101000011101111… |
… | …1100111111100010011 |
3 | 110112110010121121000222 |
4 | 1322013133213330103 |
5 | 4122014242424412 |
6 | 140123044303255 |
7 | 12321221406665 |
oct | 1720737477423 |
9 | 415403547028 |
10 | 131122233107 |
11 | 5067709a508 |
12 | 214b46a1b2b |
13 | c49853b1a8 |
14 | 64bc554535 |
15 | 362663c072 |
hex | 1e877e7f13 |
131122233107 has 2 divisors, whose sum is σ = 131122233108. Its totient is φ = 131122233106.
The previous prime is 131122233079. The next prime is 131122233133. The reversal of 131122233107 is 701332221131.
It is an a-pointer prime, because the next prime (131122233133) can be obtained adding 131122233107 to its sum of digits (26).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131122233107 - 214 = 131122216723 is a prime.
It is a super-3 number, since 3×1311222331073 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (131122233007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65561116553 + 65561116554.
It is an arithmetic number, because the mean of its divisors is an integer number (65561116554).
Almost surely, 2131122233107 is an apocalyptic number.
131122233107 is a deficient number, since it is larger than the sum of its proper divisors (1).
131122233107 is an equidigital number, since it uses as much as digits as its factorization.
131122233107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 26.
Adding to 131122233107 its reverse (701332221131), we get a palindrome (832454454238).
The spelling of 131122233107 in words is "one hundred thirty-one billion, one hundred twenty-two million, two hundred thirty-three thousand, one hundred seven".
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