13112253210040 has 16 divisors (see below), whose sum is σ = 29502569722680. Its totient is φ = 5244901284000.

The previous prime is 13112253210037. The next prime is 13112253210047. The reversal of 13112253210040 is 4001235221131.

It is a junction number, because it is equal to n+sod(n) for n = 13112253209987 and 13112253210014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13112253210047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163903165086 + ... + 163903165165.

Almost surely, 2^{13112253210040} is an apocalyptic number.

13112253210040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13112253210040 is an abundant number, since it is smaller than the sum of its proper divisors (16390316512640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13112253210040 is a wasteful number, since it uses less digits than its factorization.

13112253210040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 327806330262 (or 327806330258 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 13112253210040 its reverse (4001235221131), we get a palindrome (17113488431171).

The spelling of 13112253210040 in words is "thirteen trillion, one hundred twelve billion, two hundred fifty-three million, two hundred ten thousand, forty".