13112330310103 has 4 divisors (see below), whose sum is σ = 13297011018768. Its totient is φ = 12927649601440.

The previous prime is 13112330310097. The next prime is 13112330310151. The reversal of 13112330310103 is 30101303321131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13112330310103 - 2³⁷ = 12974891356631 is a prime.

It is a super-3 number, since 3×13112330310103³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13112330316103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92340354226 + ... + 92340354367.

It is an arithmetic number, because the mean of its divisors is an integer number (3324252754692).

Almost surely, 2^{13112330310103} is an apocalyptic number.

13112330310103 is a deficient number, since it is larger than the sum of its proper divisors (184680708665).

13112330310103 is an equidigital number, since it uses as much as digits as its factorization.

13112330310103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 184680708664.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 13112330310103 its reverse (30101303321131), we get a palindrome (43213633631234).

The spelling of 13112330310103 in words is "thirteen trillion, one hundred twelve billion, three hundred thirty million, three hundred ten thousand, one hundred three".