Base | Representation |
---|---|
bin | 10011000101001011100… |
… | …101011001110000011111 |
3 | 11122100112002110010210012 |
4 | 103011023211121300133 |
5 | 132440401134340221 |
6 | 2442212220233435 |
7 | 163506402430241 |
oct | 23051345316037 |
9 | 4570462403705 |
10 | 1311233121311 |
11 | 4660aaa05523 |
12 | 19216139b87b |
13 | 96858404999 |
14 | 4766d3c0091 |
15 | 241951b265b |
hex | 1314b959c1f |
1311233121311 has 2 divisors, whose sum is σ = 1311233121312. Its totient is φ = 1311233121310.
The previous prime is 1311233121271. The next prime is 1311233121329. The reversal of 1311233121311 is 1131213321131.
It is a strong prime.
It is an emirp because it is prime and its reverse (1131213321131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1311233121311 - 210 = 1311233120287 is a prime.
It is a super-3 number, since 3×13112331213113 (a number of 37 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311233141311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655616560655 + 655616560656.
It is an arithmetic number, because the mean of its divisors is an integer number (655616560656).
Almost surely, 21311233121311 is an apocalyptic number.
1311233121311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311233121311 is an equidigital number, since it uses as much as digits as its factorization.
1311233121311 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 324, while the sum is 23.
Adding to 1311233121311 its reverse (1131213321131), we get a palindrome (2442446442442).
The spelling of 1311233121311 in words is "one trillion, three hundred eleven billion, two hundred thirty-three million, one hundred twenty-one thousand, three hundred eleven".
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