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131123345042435 = 5231140203000369
BaseRepresentation
bin11101110100000110001000…
…011001110010110000000011
3122012021021021100220002022212
4131310012020121302300003
5114141311102312324220
61142513122204452335
736422230504054304
oct3564061031626003
9565237240802285
10131123345042435
1138864109997119
12128586bab4a0ab
135821b55a5b125
142454591cd07ab
151025c447b40c5
hex774188672c03

131123345042435 has 8 divisors (see below), whose sum is σ = 164189232053280. Its totient is φ = 100337864032384.

The previous prime is 131123345042429. The next prime is 131123345042447. The reversal of 131123345042435 is 534240543321131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131123345042435 - 210 = 131123345041411 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131123345042392 and 131123345042401.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 570101500070 + ... + 570101500299.

It is an arithmetic number, because the mean of its divisors is an integer number (20523654006660).

Almost surely, 2131123345042435 is an apocalyptic number.

131123345042435 is a deficient number, since it is larger than the sum of its proper divisors (33065887010845).

131123345042435 is a wasteful number, since it uses less digits than its factorization.

131123345042435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1140203000397.

The product of its (nonzero) digits is 518400, while the sum is 41.

Adding to 131123345042435 its reverse (534240543321131), we get a palindrome (665363888363566).

The spelling of 131123345042435 in words is "one hundred thirty-one trillion, one hundred twenty-three billion, three hundred forty-five million, forty-two thousand, four hundred thirty-five".

Divisors: 1 5 23 115 1140203000369 5701015001845 26224669008487 131123345042435