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13112355510000 = 2432541729319533
BaseRepresentation
bin1011111011001111010101…
…0010101101011011110000
31201102112021121012210220200
42332303311102231123300
53204313101002310000
643515422153035200
72522223251600055
oct276636522553360
951375247183820
1013112355510000
1141a5a1193538a
1215793193b5b00
1374164a194806
143348d9da702c
1517b138468500
hexbecf54ad6f0

13112355510000 has 1200 divisors, whose sum is σ = 51853128687360. Its totient is φ = 3074641920000.

The previous prime is 13112355509993. The next prime is 13112355510053. The reversal of 13112355510000 is 1555321131.

13112355510000 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 2 + 3 + 555 + 100 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (1200).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 239 ways as a sum of consecutive naturals, for example, 1375465234 + ... + 1375474766.

Almost surely, 213112355510000 is an apocalyptic number.

13112355510000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13112355510000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (25926564343680).

13112355510000 is an abundant number, since it is smaller than the sum of its proper divisors (38740773177360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13112355510000 is a wasteful number, since it uses less digits than its factorization.

13112355510000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9644 (or 9620 counting only the distinct ones).

The product of its (nonzero) digits is 2250, while the sum is 27.

The spelling of 13112355510000 in words is "thirteen trillion, one hundred twelve billion, three hundred fifty-five million, five hundred ten thousand".