1311254025555 has 8 divisors (see below), whose sum is σ = 2098006440912. Its totient is φ = 699335480288.

The previous prime is 1311254025551. The next prime is 1311254025577. The reversal of 1311254025555 is 5555204521131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1311254025555 - 2² = 1311254025551 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1311254025551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43708467504 + ... + 43708467533.

It is an arithmetic number, because the mean of its divisors is an integer number (262250805114).

Almost surely, 2^{1311254025555} is an apocalyptic number.

1311254025555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1311254025555 is a deficient number, since it is larger than the sum of its proper divisors (786752415357).

1311254025555 is an equidigital number, since it uses as much as digits as its factorization.

1311254025555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87416935045.

The product of its (nonzero) digits is 150000, while the sum is 39.

Adding to 1311254025555 its reverse (5555204521131), we get a palindrome (6866458546686).

The spelling of 1311254025555 in words is "one trillion, three hundred eleven billion, two hundred fifty-four million, twenty-five thousand, five hundred fifty-five".