Base | Representation |
---|---|
bin | 11000011011001100… |
… | …01101001101100111 |
3 | 1020211212110111112002 |
4 | 30031212031031213 |
5 | 203323413140122 |
6 | 10005105315515 |
7 | 642644561522 |
oct | 141546151547 |
9 | 36755414462 |
10 | 13113021287 |
11 | 5619a5aa83 |
12 | 265b635b9b |
13 | 130c9242c2 |
14 | 8c5789bb9 |
15 | 51b329992 |
hex | 30d98d367 |
13113021287 has 2 divisors, whose sum is σ = 13113021288. Its totient is φ = 13113021286.
The previous prime is 13113021199. The next prime is 13113021289. The reversal of 13113021287 is 78212031131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13113021287 - 224 = 13096244071 is a prime.
Together with 13113021289, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13113021289) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556510643 + 6556510644.
It is an arithmetic number, because the mean of its divisors is an integer number (6556510644).
Almost surely, 213113021287 is an apocalyptic number.
13113021287 is a deficient number, since it is larger than the sum of its proper divisors (1).
13113021287 is an equidigital number, since it uses as much as digits as its factorization.
13113021287 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 29.
The spelling of 13113021287 in words is "thirteen billion, one hundred thirteen million, twenty-one thousand, two hundred eighty-seven".
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