13113025241 has 2 divisors, whose sum is σ = 13113025242. Its totient is φ = 13113025240.

The previous prime is 13113025217. The next prime is 13113025243. The reversal of 13113025241 is 14252031131.

13113025241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7305975625 + 5807049616 = 85475^2 + 76204^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13113025241 is a prime.

It is a super-2 number, since 2×13113025241² (a number of 21 digits) contains 22 as substring.

Together with 13113025243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13113025243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556512620 + 6556512621.

It is an arithmetic number, because the mean of its divisors is an integer number (6556512621).

Almost surely, 2^13113025241 is an apocalyptic number.

It is an amenable number.

13113025241 is a deficient number, since it is larger than the sum of its proper divisors (1).

13113025241 is an equidigital number, since it uses as much as digits as its factorization.

13113025241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 13113025241 its reverse (14252031131), we get a palindrome (27365056372).

The spelling of 13113025241 in words is "thirteen billion, one hundred thirteen million, twenty-five thousand, two hundred forty-one".