Base | Representation |
---|---|
bin | 11101110100001100101000… |
… | …010100111110100110101000 |
3 | 122012021221021200100020122212 |
4 | 131310030220110332212220 |
5 | 114141414400203231440 |
6 | 1142520234440504252 |
7 | 36422565435433526 |
oct | 3564145024764650 |
9 | 565257250306585 |
10 | 131130323102120 |
11 | 3886706a9156a1 |
12 | 12859b27a7b088 |
13 | 58226c8651724 |
14 | 2454a54979316 |
15 | 10260021e7465 |
hex | 77432853e9a8 |
131130323102120 has 32 divisors (see below), whose sum is σ = 295046036611200. Its totient is φ = 52451629750848.
The previous prime is 131130323102101. The next prime is 131130323102183. The reversal of 131130323102120 is 21201323031131.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11341700 + ... + 19771059.
It is an arithmetic number, because the mean of its divisors is an integer number (9220188644100).
Almost surely, 2131130323102120 is an apocalyptic number.
131130323102120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131130323102120 is an abundant number, since it is smaller than the sum of its proper divisors (163915713509080).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131130323102120 is a wasteful number, since it uses less digits than its factorization.
131130323102120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31218137 (or 31218133 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 131130323102120 its reverse (21201323031131), we get a palindrome (152331646133251).
The spelling of 131130323102120 in words is "one hundred thirty-one trillion, one hundred thirty billion, three hundred twenty-three million, one hundred two thousand, one hundred twenty".
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