Base | Representation |
---|---|
bin | 111101000100000000… |
… | …1000100010111111000 |
3 | 110112110202010000101021 |
4 | 1322020001010113320 |
5 | 4122024014002222 |
6 | 140124000232224 |
7 | 12321356053234 |
oct | 1721001042770 |
9 | 415422100337 |
10 | 131131000312 |
11 | 50681038434 |
12 | 214b760b674 |
13 | c49a2ba8a0 |
14 | 64bd7975c4 |
15 | 36272beac7 |
hex | 1e880445f8 |
131131000312 has 16 divisors (see below), whose sum is σ = 264783750840. Its totient is φ = 60522000096.
The previous prime is 131131000307. The next prime is 131131000313. The reversal of 131131000312 is 213000131131.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131131000313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 630437398 + ... + 630437605.
Almost surely, 2131131000312 is an apocalyptic number.
It is an amenable number.
131131000312 is an abundant number, since it is smaller than the sum of its proper divisors (133652750528).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131131000312 is a wasteful number, since it uses less digits than its factorization.
131131000312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1260875022 (or 1260875018 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 131131000312 its reverse (213000131131), we get a palindrome (344131131443).
The spelling of 131131000312 in words is "one hundred thirty-one billion, one hundred thirty-one million, three hundred twelve", and thus it is an aban number.
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