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13113100102333 = 7111724189167967
BaseRepresentation
bin1011111011010010000110…
…1011000110101010111101
31201102121012111022000120111
42332310201223012222331
53204321112111233313
643520024112150021
72522250562534150
oct276644153065275
951377174260514
1013113100102333
1141a6264171650
1215794a6838311
13741738517aaa
1433496ac2bc97
1517b17d9e843d
hexbed21ac6abd

13113100102333 has 192 divisors, whose sum is σ = 18116990115840. Its totient is φ = 9211874918400.

The previous prime is 13113100102279. The next prime is 13113100102343. The reversal of 13113100102333 is 33320100131131.

It is a de Polignac number, because none of the positive numbers 2k-13113100102333 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13113100102343) by changing a digit.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 13560599416 + ... + 13560600382.

It is an arithmetic number, because the mean of its divisors is an integer number (94359323520).

Almost surely, 213113100102333 is an apocalyptic number.

It is an amenable number.

13113100102333 is a deficient number, since it is larger than the sum of its proper divisors (5003890013507).

13113100102333 is a wasteful number, since it uses less digits than its factorization.

13113100102333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1316 (or 1299 counting only the distinct ones).

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 13113100102333 its reverse (33320100131131), we get a palindrome (46433200233464).

The spelling of 13113100102333 in words is "thirteen trillion, one hundred thirteen billion, one hundred million, one hundred two thousand, three hundred thirty-three".