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13113100112310 = 23351119141115623
BaseRepresentation
bin1011111011010010000110…
…1011001001000110110110
31201102121012111022112021000
42332310201223021012312
53204321112112043220
643520024112304130
72522250562605222
oct276644153110666
951377174275230
1013113100112310
1141a62641790a0
1215794a6842046
1374173851c4b3
1433496ac31782
1517b17d9eb390
hexbed21ac91b6

13113100112310 has 256 divisors, whose sum is σ = 38363073085440. Its totient is φ = 3160958256000.

The previous prime is 13113100112309. The next prime is 13113100112323. The reversal of 13113100112310 is 1321100131131.

13113100112310 is a `hidden beast` number, since 1 + 31 + 1 + 310 + 0 + 1 + 12 + 310 = 666.

It is a super-2 number, since 2×131131001123102 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 2332044159 + ... + 2332049781.

It is an arithmetic number, because the mean of its divisors is an integer number (149855754240).

Almost surely, 213113100112310 is an apocalyptic number.

13113100112310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 13113100112310, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19181536542720).

13113100112310 is an abundant number, since it is smaller than the sum of its proper divisors (25249972973130).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13113100112310 is a wasteful number, since it uses less digits than its factorization.

13113100112310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9952 (or 9946 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 13113100112310 its reverse (1321100131131), we get a palindrome (14434200243441).

The spelling of 13113100112310 in words is "thirteen trillion, one hundred thirteen billion, one hundred million, one hundred twelve thousand, three hundred ten".