131131200000 has 480 divisors, whose sum is σ = 462622140288. Its totient is φ = 32890880000.

The previous prime is 131131199999. The next prime is 131131200023. The reversal of 131131200000 is 2131131.

It is a tau number, because it is divible by the number of its divisors (480).

It is a super-2 number, since 2×131131200000² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 81599197 + ... + 81600803.

Almost surely, 2^131131200000 is an apocalyptic number.

131131200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131131200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (231311070144).

131131200000 is an abundant number, since it is smaller than the sum of its proper divisors (331490940288).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131131200000 is an frugal number, since it uses more digits than its factorization.

131131200000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1670 (or 1634 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 131131200000 its reverse (2131131), we get a palindrome (131133331131).

The spelling of 131131200000 in words is "one hundred thirty-one billion, one hundred thirty-one million, two hundred thousand".