Base | Representation |
---|---|
bin | 100111000101001… |
… | …1000011010101100 |
3 | 10101101112012012102 |
4 | 1032022120122230 |
5 | 10141201004200 |
6 | 334042354232 |
7 | 44332146140 |
oct | 11612303254 |
9 | 3341465172 |
10 | 1311344300 |
11 | 613246422 |
12 | 3071bb978 |
13 | 17b8aa696 |
14 | c6235220 |
15 | 7a1d16d5 |
hex | 4e2986ac |
1311344300 has 144 divisors (see below), whose sum is σ = 3464778240. Its totient is φ = 420541440.
The previous prime is 1311344263. The next prime is 1311344303. The reversal of 1311344300 is 34431131.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is not an unprimeable number, because it can be changed into a prime (1311344303) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3129491 + ... + 3129909.
It is an arithmetic number, because the mean of its divisors is an integer number (24060960).
Almost surely, 21311344300 is an apocalyptic number.
1311344300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1311344300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1732389120).
1311344300 is an abundant number, since it is smaller than the sum of its proper divisors (2153433940).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311344300 is a wasteful number, since it uses less digits than its factorization.
1311344300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 720 (or 713 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 20.
The square root of 1311344300 is about 36212.4881774230. The cubic root of 1311344300 is about 1094.5583312210.
Adding to 1311344300 its reverse (34431131), we get a palindrome (1345775431).
It can be divided in two parts, 131 and 1344300, that added together give a palindrome (1344431).
The spelling of 1311344300 in words is "one billion, three hundred eleven million, three hundred forty-four thousand, three hundred".
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