131140205213130 has 24 divisors (see below), whose sum is σ = 340964533554372. Its totient is φ = 34970721390144.

The previous prime is 131140205213107. The next prime is 131140205213153. The reversal of 131140205213130 is 31312502041131.

131140205213130 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 4 + 0 + 2 + 0 + 521 + 3 + 130 = 666.

It is an interprime number because it is at equal distance from previous prime (131140205213107) and next prime (131140205213153).

It can be written as a sum of positive squares in 2 ways, for example, as 126307546027569 + 4832659185561 = 11238663^2 + 2198331^2 .

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 131140205213094 and 131140205213103.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 728556695539 + ... + 728556695718.

Almost surely, 2^{131140205213130} is an apocalyptic number.

131140205213130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131140205213130 is an abundant number, since it is smaller than the sum of its proper divisors (209824328341242).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131140205213130 is a wasteful number, since it uses less digits than its factorization.

131140205213130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1457113391270 (or 1457113391267 counting only the distinct ones).

The product of its (nonzero) digits is 2160, while the sum is 27.

Adding to 131140205213130 its reverse (31312502041131), we get a palindrome (162452707254261).

The spelling of 131140205213130 in words is "one hundred thirty-one trillion, one hundred forty billion, two hundred five million, two hundred thirteen thousand, one hundred thirty".