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13114112024000 = 265313215164237
BaseRepresentation
bin1011111011010101110111…
…1111010001110111000000
31201102200211000101222010202
42332311131333101313000
53204330200134232000
643520312341144332
72522314630660121
oct276653577216700
951380730358122
1013114112024000
1141a6733398349
1215797296bb0a8
1374186a06a400
14334a253a0048
1517b1dc781dd5
hexbed5dfd1dc0

13114112024000 has 336 divisors, whose sum is σ = 35400957448896. Its totient is φ = 4809991680000.

The previous prime is 13114112023981. The next prime is 13114112024017. The reversal of 13114112024000 is 42021141131.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 204119882 + ... + 204184118.

Almost surely, 213114112024000 is an apocalyptic number.

13114112024000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13114112024000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17700478724448).

13114112024000 is an abundant number, since it is smaller than the sum of its proper divisors (22286845424896).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13114112024000 is a wasteful number, since it uses less digits than its factorization.

13114112024000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64441 (or 64408 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 13114112024000 its reverse (42021141131), we get a palindrome (13156133165131).

The spelling of 13114112024000 in words is "thirteen trillion, one hundred fourteen billion, one hundred twelve million, twenty-four thousand".