131141123210000 has 100 divisors (see below), whose sum is σ = 317675880640272. Its totient is φ = 52428345168000.

The previous prime is 131141123209979. The next prime is 131141123210003. The reversal of 131141123210000 is 12321141131.

It is a tau number, because it is divible by the number of its divisors (100).

It is a Harshad number since it is a multiple of its sum of digits (20).

It is not an unprimeable number, because it can be changed into a prime (131141123210003) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 15157919 + ... + 22182081.

Almost surely, 2^{131141123210000} is an apocalyptic number.

131141123210000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131141123210000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (158837940320136).

131141123210000 is an abundant number, since it is smaller than the sum of its proper divisors (186534757430272).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131141123210000 is an equidigital number, since it uses as much as digits as its factorization.

131141123210000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7026058 (or 7026037 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 131141123210000 its reverse (12321141131), we get a palindrome (131153444351131).

The spelling of 131141123210000 in words is "one hundred thirty-one trillion, one hundred forty-one billion, one hundred twenty-three million, two hundred ten thousand".