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1311412526135 = 5262282505227
BaseRepresentation
bin10011000101010110010…
…001110001110000110111
311122100222121000211221022
4103011112101301300313
5132441233101314020
62442242105411355
7163514011356335
oct23052621616067
94570877024838
101311412526135
11466192200a78
121921b1499b5b
139688662a99a
1447689160b55
15241a5cee625
hex13156471c37

1311412526135 has 4 divisors (see below), whose sum is σ = 1573695031368. Its totient is φ = 1049130020904.

The previous prime is 1311412526077. The next prime is 1311412526143. The reversal of 1311412526135 is 5316252141131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311412526135 - 212 = 1311412522039 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311412526095 and 1311412526104.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131141252609 + ... + 131141252618.

It is an arithmetic number, because the mean of its divisors is an integer number (393423757842).

Almost surely, 21311412526135 is an apocalyptic number.

1311412526135 is a deficient number, since it is larger than the sum of its proper divisors (262282505233).

1311412526135 is an equidigital number, since it uses as much as digits as its factorization.

1311412526135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 262282505232.

The product of its digits is 21600, while the sum is 35.

Adding to 1311412526135 its reverse (5316252141131), we get a palindrome (6627664667266).

The spelling of 1311412526135 in words is "one trillion, three hundred eleven billion, four hundred twelve million, five hundred twenty-six thousand, one hundred thirty-five".

Divisors: 1 5 262282505227 1311412526135