Base | Representation |
---|---|
bin | 10011000101010110010… |
… | …001110001110000110111 |
3 | 11122100222121000211221022 |
4 | 103011112101301300313 |
5 | 132441233101314020 |
6 | 2442242105411355 |
7 | 163514011356335 |
oct | 23052621616067 |
9 | 4570877024838 |
10 | 1311412526135 |
11 | 466192200a78 |
12 | 1921b1499b5b |
13 | 9688662a99a |
14 | 47689160b55 |
15 | 241a5cee625 |
hex | 13156471c37 |
1311412526135 has 4 divisors (see below), whose sum is σ = 1573695031368. Its totient is φ = 1049130020904.
The previous prime is 1311412526077. The next prime is 1311412526143. The reversal of 1311412526135 is 5316252141131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1311412526135 - 212 = 1311412522039 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1311412526095 and 1311412526104.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131141252609 + ... + 131141252618.
It is an arithmetic number, because the mean of its divisors is an integer number (393423757842).
Almost surely, 21311412526135 is an apocalyptic number.
1311412526135 is a deficient number, since it is larger than the sum of its proper divisors (262282505233).
1311412526135 is an equidigital number, since it uses as much as digits as its factorization.
1311412526135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 262282505232.
The product of its digits is 21600, while the sum is 35.
Adding to 1311412526135 its reverse (5316252141131), we get a palindrome (6627664667266).
The spelling of 1311412526135 in words is "one trillion, three hundred eleven billion, four hundred twelve million, five hundred twenty-six thousand, one hundred thirty-five".
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