Base | Representation |
---|---|
bin | 10011000101010110010… |
… | …100100000000011100111 |
3 | 11122100222122101010020012 |
4 | 103011112110200003213 |
5 | 132441233242140124 |
6 | 2442242133000435 |
7 | 163514020421600 |
oct | 23052624400347 |
9 | 4570878333205 |
10 | 1311413240039 |
11 | 466192649381 |
12 | 1921b178311b |
13 | 9688681a906 |
14 | 476892a8da7 |
15 | 241a5de0e0e |
hex | 131565200e7 |
1311413240039 has 12 divisors (see below), whose sum is σ = 1539021721104. Its totient is φ = 1114120977984.
The previous prime is 1311413240029. The next prime is 1311413240087. The reversal of 1311413240039 is 9300423141131.
It is not a de Polignac number, because 1311413240039 - 228 = 1311144804583 is a prime.
It is a super-2 number, since 2×13114132400392 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1311413239987 and 1311413240014.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311413240029) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 118417187 + ... + 118428260.
It is an arithmetic number, because the mean of its divisors is an integer number (128251810092).
Almost surely, 21311413240039 is an apocalyptic number.
1311413240039 is a deficient number, since it is larger than the sum of its proper divisors (227608481065).
1311413240039 is a wasteful number, since it uses less digits than its factorization.
1311413240039 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 236845574 (or 236845567 counting only the distinct ones).
The product of its (nonzero) digits is 7776, while the sum is 32.
The spelling of 1311413240039 in words is "one trillion, three hundred eleven billion, four hundred thirteen million, two hundred forty thousand, thirty-nine".
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