131141324323040 has 48 divisors (see below), whose sum is σ = 315072588544560. Its totient is φ = 51567436001280.

The previous prime is 131141324323027. The next prime is 131141324323063. The reversal of 131141324323040 is 40323423141131.

It is a Harshad number since it is a multiple of its sum of digits (32).

It is a junction number, because it is equal to n+sod(n) for n = 131141324322988 and 131141324323006.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6946035281 + ... + 6946054160.

It is an arithmetic number, because the mean of its divisors is an integer number (6564012261345).

Almost surely, 2^{131141324323040} is an apocalyptic number.

131141324323040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131141324323040 is an abundant number, since it is smaller than the sum of its proper divisors (183931264221520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131141324323040 is a wasteful number, since it uses less digits than its factorization.

131141324323040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13892089515 (or 13892089507 counting only the distinct ones).

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 131141324323040 its reverse (40323423141131), we get a palindrome (171464747464171).

The spelling of 131141324323040 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred twenty-four million, three hundred twenty-three thousand, forty".