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131141341010021 is a prime number
BaseRepresentation
bin11101110100010110111001…
…000010111101100001100101
3122012022222201112110221220212
4131310112321002331201211
5114142104431244310041
61142525300024505205
736423435453213146
oct3564267102754145
9565288645427825
10131141341010021
1138870804174a01
12128600a191b205
1358237631a9164
1424553bbd8bacd
1510264496228eb
hex7745b90bd865

131141341010021 has 2 divisors, whose sum is σ = 131141341010022. Its totient is φ = 131141341010020.

The previous prime is 131141341009981. The next prime is 131141341010039. The reversal of 131141341010021 is 120010143141131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 71095672830625 + 60045668179396 = 8431825^2 + 7748914^2 .

It is an emirp because it is prime and its reverse (120010143141131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131141341010021 - 222 = 131141336815717 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131141341010621) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65570670505010 + 65570670505011.

It is an arithmetic number, because the mean of its divisors is an integer number (65570670505011).

Almost surely, 2131141341010021 is an apocalyptic number.

It is an amenable number.

131141341010021 is a deficient number, since it is larger than the sum of its proper divisors (1).

131141341010021 is an equidigital number, since it uses as much as digits as its factorization.

131141341010021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 131141341010021 its reverse (120010143141131), we get a palindrome (251151484151152).

The spelling of 131141341010021 in words is "one hundred thirty-one trillion, one hundred forty-one billion, three hundred forty-one million, ten thousand, twenty-one".