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131142101243806 = 265571050621903
BaseRepresentation
bin11101110100010111100110…
…010111000001011110011110
3122012100001200111222211121201
4131310113212113001132132
5114142113010404300211
61142525503303150114
736423463344124162
oct3564274627013636
9565301614884551
10131142101243806
1138871064314894
121286027444533a
135823854847a33
142455450d24ca2
1510264912420c1
hex7745e65c179e

131142101243806 has 4 divisors (see below), whose sum is σ = 196713151865712. Its totient is φ = 65571050621902.

The previous prime is 131142101243801. The next prime is 131142101243807. The reversal of 131142101243806 is 608342101241131.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131142101243801) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32785525310950 + ... + 32785525310953.

It is an arithmetic number, because the mean of its divisors is an integer number (49178287966428).

Almost surely, 2131142101243806 is an apocalyptic number.

131142101243806 is a deficient number, since it is larger than the sum of its proper divisors (65571050621906).

131142101243806 is an equidigital number, since it uses as much as digits as its factorization.

131142101243806 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65571050621905.

The product of its (nonzero) digits is 27648, while the sum is 37.

Adding to 131142101243806 its reverse (608342101241131), we get a palindrome (739484202484937).

The spelling of 131142101243806 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred one million, two hundred forty-three thousand, eight hundred six".

Divisors: 1 2 65571050621903 131142101243806