Base | Representation |
---|---|
bin | 11101110100010111100110… |
… | …010111000001011110011110 |
3 | 122012100001200111222211121201 |
4 | 131310113212113001132132 |
5 | 114142113010404300211 |
6 | 1142525503303150114 |
7 | 36423463344124162 |
oct | 3564274627013636 |
9 | 565301614884551 |
10 | 131142101243806 |
11 | 38871064314894 |
12 | 1286027444533a |
13 | 5823854847a33 |
14 | 2455450d24ca2 |
15 | 10264912420c1 |
hex | 7745e65c179e |
131142101243806 has 4 divisors (see below), whose sum is σ = 196713151865712. Its totient is φ = 65571050621902.
The previous prime is 131142101243801. The next prime is 131142101243807. The reversal of 131142101243806 is 608342101241131.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131142101243801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32785525310950 + ... + 32785525310953.
It is an arithmetic number, because the mean of its divisors is an integer number (49178287966428).
Almost surely, 2131142101243806 is an apocalyptic number.
131142101243806 is a deficient number, since it is larger than the sum of its proper divisors (65571050621906).
131142101243806 is an equidigital number, since it uses as much as digits as its factorization.
131142101243806 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65571050621905.
The product of its (nonzero) digits is 27648, while the sum is 37.
Adding to 131142101243806 its reverse (608342101241131), we get a palindrome (739484202484937).
The spelling of 131142101243806 in words is "one hundred thirty-one trillion, one hundred forty-two billion, one hundred one million, two hundred forty-three thousand, eight hundred six".
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