1311422551540 has 12 divisors (see below), whose sum is σ = 2753987358276. Its totient is φ = 524569020608.

The previous prime is 1311422551519. The next prime is 1311422551541. The reversal of 1311422551540 is 451552241131.

It can be written as a sum of positive squares in 2 ways, for example, as 501382951056 + 810039600484 = 708084^2 + 900022^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1311422551496 and 1311422551505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311422551541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32785563769 + ... + 32785563808.

It is an arithmetic number, because the mean of its divisors is an integer number (229498946523).

Almost surely, 2^{1311422551540} is an apocalyptic number.

1311422551540 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1311422551540 is an abundant number, since it is smaller than the sum of its proper divisors (1442564806736).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311422551540 is a wasteful number, since it uses less digits than its factorization.

1311422551540 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65571127586 (or 65571127584 counting only the distinct ones).

The product of its (nonzero) digits is 24000, while the sum is 34.

Adding to 1311422551540 its reverse (451552241131), we get a palindrome (1762974792671).

The spelling of 1311422551540 in words is "one trillion, three hundred eleven billion, four hundred twenty-two million, five hundred fifty-one thousand, five hundred forty".